,

Since they are equilaterals so each of their sides are equal.

$$\overline{AE} = \overline{AC} +\overline{CE}$$

,

\begin{eqnarray*}
\left(\overline{AB}+\overline{BC}+\overline{AC}\right)+\left(\overline{CD}+\overline{DE}+\overline{CE}\right) & = & 3\left(\overline{AC}\right)+3\left(\overline{CE}\right)\\
& = & 3\left(\overline{AC}+\overline{CE}\right)\\
& = & 3\left(\overline{AE}\right)\\
& = & 3\times35\\
& = & 105
\end{eqnarray*}