$\displaystyle \frac{(x+1)^2}{24} - \frac{(y-1)^2}{12} = 1$ $\displaystyle \frac{(x+1)^2}{12} - \frac{(y-1)^2}{24} = 1$ $\displaystyle \frac{(x-1)^2}{12} - \frac{(y+1)^2}{24} = 1$ $\displaystyle {(x+1)^2} - \frac{(y-1)^2}{2} = 1$ $\displaystyle {(x-1)^2} - \frac{(y+1)^2}{2} = 1$